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Overview

Probability questions often reduce to counting. Define a clear sample space, count favorable outcomes, and use complements when easier.

Key Ideas

  • P(A)=favorabletotalP(A) = \frac{\text{favorable}}{\text{total}} when outcomes are equally likely.
  • P(Ac)=1P(A)P(A^c) = 1 - P(A) is often simpler to compute.
  • Use the rule of product to count outcomes in multi-step experiments.

Worked Example

Two fair dice are rolled. What is the probability the sum is 77?

There are 3636 equally likely outcomes. The favorable pairs are (1,6),(2,5),(3,4),(4,3),(5,2),(6,1)(1,6),(2,5),(3,4),(4,3),(5,2),(6,1), so the probability is 636=16\frac{6}{36}=\frac{1}{6}.

Common Pitfalls

  • Assuming outcomes are equally likely without checking.
  • Forgetting to count order when it matters.

Practice Problems

StatusSourceProblem NameDifficultyTags
AMC 8Normal
Show TagsCounting, Probability
AMC 10Normal
Show TagsComplement, Probability

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