Join the USAMO Guide Discord Server. Regular updates are posted there!

Let me Join!
Dismiss

HMMT November 2021 #0kiz

HMMT November 2021Hard

From module Telescoping Sums and Products

Community difficultyNo ratings yetBe the first to rate this problem.
Understand the scale
Scale 0.5: Easiest math competition problems, often solvable even for early middle school students without experience. 1: Problems strictly for beginners, often at a moderate middle school level. 1.5: Problems for stronger beginner students, on the level of the middling problems in most middle school contests. 2: For motivated beginners, harder questions from the previous categories. 2.5: More advanced beginner problems, hardest questions from previous categories. 3: Early intermediate problems that require more creative thinking. 3.5: Tougher early intermediate problems that consistently stretch into higher-level creative thinking or conceptual knowledge. 4: Intermediate-level problems. 4.5: Upper intermediate problems approaching the upper bound for non-invitational sprint math competitions. 5: More difficult AIME problems or simple proof-based Olympiad-style problems. 6: High-level AIME-styled questions or introductory Olympiad-level questions. 7: Tougher Olympiad-level questions, may require more technical knowledge. 8: High-level Olympiad-level questions. 9: Expert Olympiad-level questions. 9.5: The hardest problems appearing on Olympiads which the strongest students could reasonably solve. 10: Historically notorious problems, generally unsuitable for even very hard competitions because they are exceedingly tedious, long, and difficult.
Telescoping series

Problem

Problem:

There are 88 lily pads in a pond numbered 1,2,…,81, 2, \ldots, 8. A frog starts on lily pad 11. During the ii-th second, the frog jumps from lily pad ii to i+1i+1, falling into the water with probability 1i+1\frac{1}{i+1}. The probability that the frog lands safely on lily pad 88 without having fallen into the water at any point can be written as mn\frac{m}{n}, where m,nm, n are positive integers and gcd⁡(m,n)=1\operatorname{gcd}(m, n) = 1. Find 100m+n100m + n.

← Back to all problems