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Harvard-MIT Mathematics Tournament #0in4

Harvard-MIT Mathematics TournamentHard

From module Angle Chasing Mastery

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Understand the scale
Scale 0.5: Easiest math competition problems, often solvable even for early middle school students without experience. 1: Problems strictly for beginners, often at a moderate middle school level. 1.5: Problems for stronger beginner students, on the level of the middling problems in most middle school contests. 2: For motivated beginners, harder questions from the previous categories. 2.5: More advanced beginner problems, hardest questions from previous categories. 3: Early intermediate problems that require more creative thinking. 3.5: Tougher early intermediate problems that consistently stretch into higher-level creative thinking or conceptual knowledge. 4: Intermediate-level problems. 4.5: Upper intermediate problems approaching the upper bound for non-invitational sprint math competitions. 5: More difficult AIME problems or simple proof-based Olympiad-style problems. 6: High-level AIME-styled questions or introductory Olympiad-level questions. 7: Tougher Olympiad-level questions, may require more technical knowledge. 8: High-level Olympiad-level questions. 9: Expert Olympiad-level questions. 9.5: The hardest problems appearing on Olympiads which the strongest students could reasonably solve. 10: Historically notorious problems, generally unsuitable for even very hard competitions because they are exceedingly tedious, long, and difficult.
Triangle centers: centroid, incenter, circumcenter, orthocenter, Euler line, nine-point circleTriangle trigonometryTangentsCyclic quadrilateralsMenelaus' theoremHomothetyAngle chasing

Problem

Problem:

Let ω\omega denote the incircle of triangle ABCABC. The segments BCBC, CACA, and ABAB are tangent to ω\omega at DD, EE, and FF, respectively. Point PP lies on EFEF such that segment PDPD is perpendicular to BCBC. The line APAP intersects BCBC at QQ. The circles ω1\omega_1 and ω2\omega_2 pass through BB and CC, respectively, and are tangent to AQAQ at QQ; the former meets ABAB again at XX, and the latter meets ACAC again at YY. The line XYXY intersects BCBC at ZZ. Given that AB=15AB=15, BC=14BC=14, and CA=13CA=13, find ⌊XZ⋅YZ⌋\lfloor XZ \cdot YZ\rfloor.

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