Join the USAMO Guide Discord Server. Regular updates are posted there!

Let me Join!
Dismiss

Berkeley Math Circle Monthly Contest 4 #0hrd

Berkeley Math Circle Monthly Contest 4Hard

From module Sum Formulas for Powers

Community difficultyNo ratings yetBe the first to rate this problem.
Understand the scale
Scale 0.5: Easiest math competition problems, often solvable even for early middle school students without experience. 1: Problems strictly for beginners, often at a moderate middle school level. 1.5: Problems for stronger beginner students, on the level of the middling problems in most middle school contests. 2: For motivated beginners, harder questions from the previous categories. 2.5: More advanced beginner problems, hardest questions from previous categories. 3: Early intermediate problems that require more creative thinking. 3.5: Tougher early intermediate problems that consistently stretch into higher-level creative thinking or conceptual knowledge. 4: Intermediate-level problems. 4.5: Upper intermediate problems approaching the upper bound for non-invitational sprint math competitions. 5: More difficult AIME problems or simple proof-based Olympiad-style problems. 6: High-level AIME-styled questions or introductory Olympiad-level questions. 7: Tougher Olympiad-level questions, may require more technical knowledge. 8: High-level Olympiad-level questions. 9: Expert Olympiad-level questions. 9.5: The hardest problems appearing on Olympiads which the strongest students could reasonably solve. 10: Historically notorious problems, generally unsuitable for even very hard competitions because they are exceedingly tedious, long, and difficult.
Sums and products

Problem

Problem: Evaluate the sum

11+tan⁡1∘+11+tan⁡2∘+11+tan⁡3∘+⋯+11+tan⁡89∘\frac{1}{1+\tan 1^{\circ}}+\frac{1}{1+\tan 2^{\circ}}+\frac{1}{1+\tan 3^{\circ}}+\cdots+\frac{1}{1+\tan 89^{\circ}}

(The tangent (tan⁡)(\tan) of an angle α\alpha is the ratio BC/ACBC/AC in a right triangle ABCABC with ∠C=90∘\angle C=90^{\circ} and ∠A=α\angle A=\alpha, and its value does not depend on the triangle used.)

← Back to all problems