Join the USAMO Guide Discord Server. Regular updates are posted there!

Let me Join!
Dismiss

Problem 7 (2020 AIME II)

AIME 2020
Community difficultyNo ratings yetBe the first to rate this problem.
Understand the scale
Scale 0.5: Easiest math competition problems, often solvable even for early middle school students without experience. 1: Problems strictly for beginners, often at a moderate middle school level. 1.5: Problems for stronger beginner students, on the level of the middling problems in most middle school contests. 2: For motivated beginners, harder questions from the previous categories. 2.5: More advanced beginner problems, hardest questions from previous categories. 3: Early intermediate problems that require more creative thinking. 3.5: Tougher early intermediate problems that consistently stretch into higher-level creative thinking or conceptual knowledge. 4: Intermediate-level problems. 4.5: Upper intermediate problems approaching the upper bound for non-invitational sprint math competitions. 5: More difficult AIME problems or simple proof-based Olympiad-style problems. 6: High-level AIME-styled questions or introductory Olympiad-level questions. 7: Tougher Olympiad-level questions, may require more technical knowledge. 8: High-level Olympiad-level questions. 9: Expert Olympiad-level questions. 9.5: The hardest problems appearing on Olympiads which the strongest students could reasonably solve. 10: Historically notorious problems, generally unsuitable for even very hard competitions because they are exceedingly tedious, long, and difficult.

Suggest tags for this problem

This problem does not have any tags yet. Add a few useful tags and once enough people agree, they will be added here automatically.

Problem

Two congruent right circular cones each with base radius 33 and height 88 have the axes of symmetry that intersect at right angles at a point in the interior of the cones a distance 33 from the base of each cone. A sphere with radius rr lies within both cones. The maximum possible value of r2r^2 is mn\frac{m}{n} , where mm and nn are relatively prime positive integers. Find m+nm+n .

← Back to all problems