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Overview

Intermediate probability uses conditioning and structure to simplify counting.

Key Ideas

  • P(AB)=P(AB)P(B)P(A\mid B)=\frac{P(A\cap B)}{P(B)}.
  • Expected value is linear: E[X+Y]=E[X]+E[Y]E[X+Y]=E[X]+E[Y].
  • Use complementary events to avoid messy direct counts.

Worked Example

Two cards are drawn without replacement from a standard deck. Find the probability both are aces.

There are 44 aces in 5252 cards. The probability is 452351=1221.\frac{4}{52}\cdot\frac{3}{51}=\frac{1}{221}.

Practice Problems

StatusSourceProblem NameDifficultyTags
AMC 12Normal
Show TagsConditional Probability
AIMEHard
Show TagsExpected Value

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