Overview

A defined operation problem will usually give you a made up mathematical operation defined through a custom symbol, such as a⋆ba \star b or a⋄ba \diamond b, and tell you what it equals in terms of aa and bb. Then, the problem will ask you to evaluate a specific expression or determine the value of a number aa or bb such that an expression involving the defined operation holds true. These problems test careful substitution and order of operations so it is important that you ensure accurate calculations.

Key Ideas

  • Treat the defined symbol as a function of its inputs.
  • Substitute the given values exactly where the definition tells you to.
  • If the operation is nested (e.g., 2⋆(3⋆4)2 \star (3 \star 4)), evaluate the inner operation first.
  • Watch for non-commutativity: a⋆ba \star b may differ from b⋆ab \star a.

Core Skills

Direct Substitution

Direct substituion is simply solving a defined operation problem by substituting the given values into the operation function.

Demo Problem: Given that a⋄b=2a+b2a \diamond b = 2a + b^2, find 3⋄43 \diamond 4.

We solve this problem by directly substituting in a=3a=3 and b=4b=4:

3⋄4=2(3)+42=6+16=223 \diamond 4=2(3)+4^2=6+16=\boxed{22}

It is important to ensure that we don't get aa and bb messed up and use a=4a=4 and b=3b=3.

Nested Operations

When nested operations are involved in a given expression, ensure that you first compute the inner result, and then feed it into the outer operation.

Demo Problem: Given that a⊕b=(2a)2+3ba \oplus b = (2a)^2 + 3b, find 3⊕(4⊕5)3 \oplus (4 \oplus 5).

We solve this problem by first evaluating (4⊕5)(4 \oplus 5), and then using that value to evaluate 3⊕(4⊕5).3 \oplus (4 \oplus 5).

4⊕5=(2⋅4)2+3(5)=64+15=793⊕(4⊕5)=3⊕79=(2⋅3)2+3(79)=36+237=2734 \oplus 5=(2\cdot4)^2+3(5)=64+15=79\\ 3 \oplus (4 \oplus 5) = 3 \oplus 79=(2 \cdot 3)^2+3(79)=36+237=\boxed{273}

Finding Unknowns

We often asked to determine the value of unknown variables used in defined operation expressions.

Demo Problem: If x⋆5=20x \star 5 = 20 and a⋆b=ab−aa \star b = ab - a, determine the value of xx.

It suffices to substitute a=xa=x and b=5b=5 and solve the resulting algebraic equation.

x⋆5=20x(5)−x=204x=20x=5x \star 5=20\\ x(5)-x=20\\ 4x=20\\ x=\boxed{5}

Practice Problems

StatusSourceProblem NameDifficultyTags
AMC 8Easy
Show TagsNumber Systems, Place Value
AMC 8Easy
Show TagsDefined Operations, Order of Operations
AMC 10Easy
Show TagsDefined Operations, Substitution

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