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Overview

At AIME level, inequalities need structure. You will often combine AM-GM with clever substitutions or homogenization.

Key Ideas

  • Cauchy in Engel form: ∑a2b≥(a+b+c)2b+c+a\sum \frac{a^2}{b} \ge \frac{(a+b+c)^2}{b+c+a}.
  • Jensen applies to convex functions; start with simple cases.
  • Look for symmetry and equality cases to guide algebra.

Core Skills

Homogenize

If an inequality is not homogeneous, scale variables to introduce a fixed sum or product.

Use Substitutions

Try a=xya=xy, b=yzb=yz, c=zxc=zx or a=x+ya=x+y to simplify symmetric expressions.

Track Equality

Check when equality holds and use it to guide substitutions or case splits.

Worked Example

For a,b>0a,b>0, show a2b+b2a≥a+b\frac{a^2}{b}+\frac{b^2}{a}\ge a+b.

By Cauchy, a2b+b2a≥(a+b)2a+b=a+b\frac{a^2}{b}+\frac{b^2}{a}\ge \frac{(a+b)^2}{a+b}=a+b.

More Examples

Example 1: AM-GM Chain

For a,b,c>0a,b,c>0, show a+b+c≥3abc3a+b+c \ge 3\sqrt[3]{abc}.

Apply AM-GM to three variables.

Example 2: Engel Form

Show ∑a2b≥(a+b+c)2a+b+c\sum \frac{a^2}{b} \ge \frac{(a+b+c)^2}{a+b+c}.

Apply Engel form directly.

Example 3: Symmetry

If a+b+c=1a+b+c=1, find the minimum of a2+b2+c2a^2+b^2+c^2.

It is 1/31/3 at a=b=c=1/3a=b=c=1/3.

Example 4: uvw Principle (very important! Must know for Tejs' Theorem in Level 4!)

Let a,b,c>0a,b,c>0 and a+b+c=3a+b+c=3. Your goal is show that the following expression is true:

1a+1b+1c≥a2+b2+c2+3.\frac1a+\frac1b+\frac1c \ge a^2+b^2+c^2+3.

First, by the uvw principle, we can set b=c=xb=c=x and a=3−2xa=3-2x. Therefore, the inequality thus reduces to

(x−1)2(2x+1)(2x2+2x+3)x(3−2x)≥0,\frac{(x-1)^2(2x+1)(2x^2+2x+3)}{x(3-2x)} \ge 0,

and the conclusion from here is immediate.

Example 5: Engel and Cauchy

Your job is to show that

(a+b)2b+c+(b+c)2c+a+(c+a)2a+b≥2(a+b+c).\frac{(a+b)^2}{b+c} +\frac{(b+c)^2}{c+a} +\frac{(c+a)^2}{a+b} \ge 2(a+b+c).

We can simply expand the numerators and apply Engel form to the quadratic terms. Then, we can apply cauchy or nesbitt's inequalty to finish the problem!

Example 6: Ravi Substitution (very important! Must know!)

Let x,y,zx,y,z be the side lengths of a triangle. Your goal is to show that

x2y+z−x+y2z+x−y+z2x+y−z≥x+y+z.\frac{x^2}{y+z-x} +\frac{y^2}{z+x-y} +\frac{z^2}{x+y-z} \ge x+y+z.

We can use Ravi's substitution here:

x=v+w,y=w+u,z=u+v.x=v+w,\quad y=w+u,\quad z=u+v.

Thus, the inequality becomes:

∑(v+w)22u≥2(u+v+w),\sum \frac{(v+w)^2}{2u} \ge 2(u+v+w),

and the conclusion simply follows from the Engel form.

Example 7: Hölder and Power Mean (EXTREMELY IMPORTANT!)

Your job is to show that:

(a+b+c)4≤27(a4+b4+c4).(a+b+c)^4 \le 27(a^4+b^4+c^4).

We can first apply Hölder's inequality:

(a+b+c)4≤(a4+b4+c4)(1+1+1)3.(a+b+c)^4 \le (a^4+b^4+c^4)(1+1+1)^3.

Now, since (1+1+1)3=27(1+1+1)^3=27, the result follows.

Example 8: Jensen's Inequality (ALSO EXTREMELY IMPORTANT!)

Let a,b,c>0a,b,c>0 with a+b+c=1a+b+c=1. Your goal is to show that:

ln⁡(1+a)+ln⁡(1+b)+ln⁡(1+c)≤3ln⁡(43).\ln(1+a)+\ln(1+b)+\ln(1+c) \le 3\ln\left(\frac43\right).

First, notice that since ln⁡(1+x)\ln(1+x) is concave, Jensen gives

∑ln⁡(1+a)3≤ln⁡(1+13).\frac{\sum \ln(1+a)}3 \le \ln\left(1+\frac13\right).

And multiplying this by 33 gives the result

Example 9: Muirhead (ALSO ALSO EXTREMELY IMPORTANT!)

Your goal is to show that:

a4+b4+c4+abc(a+b+c)≥∑syma3b.a^4+b^4+c^4+abc(a+b+c) \ge \sum_{\mathrm{sym}} a^3b.

First, notice that since (4,0,0)≻(3,1,0)(4,0,0)\succ(3,1,0), Muirhead gives

3(a4+b4+c4)≥∑syma3b.3(a^4+b^4+c^4) \ge \sum_{\mathrm{sym}} a^3b.

Then, we can combine it with

3(a4+b4+c4)≥4abc(a+b+c),3(a^4+b^4+c^4)\ge 4abc(a+b+c),

and the result follows nicely :)

Strategy Checklist

  • Homogenize if needed.
  • Use symmetry to reduce variables.
  • Track equality conditions.

Practice Problems

StatusSourceProblem NameDifficultyTags
AIMEVery Hard
Show TagsCauchy-Schwarz, Inequalities
AIMEHard
Show TagsAM-GM
Harvard-MIT Mathematics TournamentHard
Show TagsCatalan numbers, partitions, Muirhead / majorization
Team Selection Test 2009Hard
Show TagsMuirhead / majorization, QM-AM-GM-HM / Power Mean, Symmetric functions
Harvard-MIT Mathematics TournamentHard
Show TagsIntermediate Value Theorem, Muirhead / majorization, Polynomial operations, Symmetric functions, Vieta's formulas
Berkeley Math CircleHard
Show TagsMuirhead / majorization, QM-AM-GM-HM / Power Mean, Symmetric functions
Berkeley Math CircleHard
Show TagsColoring schemes, extremal arguments, Combinatorial optimization, Jensen / smoothing
Berkeley Math Circle Monthly Contest 3Hard
Show TagsInvariants / monovariants, Jensen / smoothing, Sums and products
BAMOHard
Show TagsGraph Theory, Jensen / smoothing, Linear and quadratic inequalities
Berkeley Math Circle Monthly Contest #1Hard
Show TagsColoring schemes, extremal arguments, Combinatorial optimization, Jensen / smoothing, Sums and products
USA IMOHard
Show TagsJensen / smoothing, Linear and quadratic inequalities, QM-AM-GM-HM / Power Mean, Quadratic functions, Triangle trigonometry, Trigonometry
Harvard-MIT November TournamentHard
Show TagsJensen / smoothing, QM-AM-GM-HM / Power Mean
2nd Annual Harvard-MIT November TournamentHard
Show TagsAlgorithms, Invariants / monovariants, Jensen / smoothing
Bay Area Mathematical OlympiadHard
Show TagsAngle chasing, Cauchy-Schwarz, Jensen / smoothing, Jensen/smoothing, QM-AM-GM-HM / Power Mean, Triangle centers: centroid, incenter, circumcenter, orthocenter, Euler line, nine-point circle, Triangle trigonometry, Trigonometry
Team Selection Test Selection TestHard
Show TagsJensen / smoothing, Jensen/smoothing, Rotation, Tangents, Translation, Triangle inequalities, Triangle trigonometry, Trigonometry, Vectors
Berkeley Math Circle Monthly Contest 4Hard
Show TagsCombinatorial optimization, Jensen / smoothing, QM-AM-GM-HM / Power Mean
HMMT 2014Hard
Show TagsJensen / smoothing
Berkeley Math Circle: Monthly Contest 2Hard
Show TagsExpected values, Jensen / smoothing
Berkeley Math Circle: Monthly Contest 5Hard
Show TagsColoring schemes, extremal arguments, Counting two ways, Jensen / smoothing
Berkeley Math CircleHard
Show TagsInduction / smoothing, Jensen / smoothing, Linear and quadratic inequalities
HMMT NovemberHard
Show TagsAlgebraic properties of binomial coefficients, Jensen / smoothing, Volume
HMMT NovemberHard
Show TagsCombinatorial optimization, Jensen / smoothing
February 2017Hard
Show TagsCombinatorial optimization, Jensen / smoothing
HMMT November 2019Hard
Show TagsJensen / smoothing
HMMT Spring 2021 Guts RoundHard
Show TagsFactorization techniques, Induction / smoothing, Invariants / monovariants, Jensen / smoothing, Sums and products

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